0=-5x^2-155x+1330

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Solution for 0=-5x^2-155x+1330 equation:



0=-5x^2-155x+1330
We move all terms to the left:
0-(-5x^2-155x+1330)=0
We add all the numbers together, and all the variables
-(-5x^2-155x+1330)=0
We get rid of parentheses
5x^2+155x-1330=0
a = 5; b = 155; c = -1330;
Δ = b2-4ac
Δ = 1552-4·5·(-1330)
Δ = 50625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50625}=225$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(155)-225}{2*5}=\frac{-380}{10} =-38 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(155)+225}{2*5}=\frac{70}{10} =7 $

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